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🧪 Chemistry  ·  Class 12  ·  NEET & JEE

Biomolecules - Practice Questions with Answers

60 free MCQs on Biomolecules with worked answers and explanations. The chemistry of life: carbohydrates, proteins, lipids, nucleic acids, enzymes, and vitamins. Understand their structures, classification, and biological functions. Highly relevant for NEET and Class 12 board exams.

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Below are 60 practice questions on Biomolecules, sorted Easy → Hard. Tap “Show answer & explanation” under any question to check yourself. Want the full theory first? Read the Biomolecules notes.

Peptide Bond Formation (Condensation)H₂N-CH(R₁)-C(=O)OHAmino acid 1+HNH-CH(R₂)-COOHAmino acid 2H₂N-CH(R₁)-CO-NH-CH(R₂)-COOHDipeptide+ H₂OThe -OH (from acid 1) and -H (from amine 2) combine to release water, forming the -CO-NH- peptide bond

Two amino acids join via a condensation reaction: the carboxyl -OH of one and an amine -H of the other are eliminated as water, leaving a peptide bond (-CO-NH-) linking them into a dipeptide; repeating this builds a full protein chain.

Easy - 20 questions

Q1.

Which biomolecule is the primary source of energy for living organisms?

  • A Carbohydrates
  • B Proteins
  • C Lipids
  • D Nucleic acids
Show answer & explanation

Answer: A. Carbohydrates

Why: Carbohydrates (glucose) are the primary and most readily available energy source for cells.

Q2.

What is the monomer unit of proteins?

  • A Amino acids
  • B Glucose
  • C Fatty acids
  • D Nucleotides
Show answer & explanation

Answer: A. Amino acids

Why: Proteins are polymers of amino acids linked by peptide bonds.

Q3.

Which bond joins amino acids in proteins?

  • A Peptide bond
  • B Glycosidic bond
  • C Phosphodiester bond
  • D Hydrogen bond
Show answer & explanation

Answer: A. Peptide bond

Why: Amino acids are joined by peptide bonds (-CO-NH-) formed by condensation reactions.

Q4.

What is the monomer of starch and cellulose?

  • A Glucose
  • B Fructose
  • C Galactose
  • D Sucrose
Show answer & explanation

Answer: A. Glucose

Why: Both starch and cellulose are polysaccharides made up of glucose monomers.

Q5.

Which monosaccharide is found in blood as blood sugar?

  • A Fructose
  • B Glucose
  • C Galactose
  • D Sucrose
Show answer & explanation

Answer: B. Glucose

Why: Glucose is the blood sugar and the primary fuel for cellular respiration.

Q6.

DNA stands for:

  • A Deoxyribonucleic acid
  • B Diribonucleic acid
  • C Dinucleic acid
  • D Dinitrogenous acid
Show answer & explanation

Answer: A. Deoxyribonucleic acid

Why: DNA is deoxyribonucleic acid, the carrier of genetic information.

Q7.

Which base is present in DNA but NOT in RNA?

  • A Thymine
  • B Uracil
  • C Adenine
  • D Guanine
Show answer & explanation

Answer: A. Thymine

Why: DNA contains thymine (T) while RNA has uracil (U) instead.

Q8.

Which base is present in RNA but NOT in DNA?

  • A Uracil
  • B Thymine
  • C Cytosine
  • D Guanine
Show answer & explanation

Answer: A. Uracil

Why: RNA contains uracil instead of thymine found in DNA.

Q9.

The double helix structure of DNA was proposed by:

  • A Watson and Crick
  • B Pauling and Corey
  • C Chargaff
  • D Rosalind Franklin
Show answer & explanation

Answer: A. Watson and Crick

Why: Watson and Crick proposed the double helix model of DNA in 1953.

Q10.

Which enzyme digests starch in saliva?

  • A Amylase
  • B Lipase
  • C Protease
  • D Cellulase
Show answer & explanation

Answer: A. Amylase

Why: Salivary amylase begins starch digestion in the mouth.

Q11.

Fats are esters of glycerol and:

  • A Fatty acids
  • B Amino acids
  • C Nucleotides
  • D Glucose
Show answer & explanation

Answer: A. Fatty acids

Why: Triglycerides (fats) are formed by esterification of glycerol with three fatty acid molecules.

Q12.

Which vitamin is produced by the body when exposed to sunlight?

  • A Vitamin D
  • B Vitamin C
  • C Vitamin A
  • D Vitamin B12
Show answer & explanation

Answer: A. Vitamin D

Why: Vitamin D is synthesised in the skin upon UV exposure from sunlight.

Q13.

Sucrose is a disaccharide made of:

  • A Glucose and fructose
  • B Glucose and glucose
  • C Glucose and galactose
  • D Fructose and galactose
Show answer & explanation

Answer: A. Glucose and fructose

Why: Sucrose (table sugar) is a disaccharide of glucose and fructose linked by a glycosidic bond.

Q14.

Which type of RNA carries amino acids to the ribosome during protein synthesis?

  • A tRNA
  • B mRNA
  • C rRNA
  • D snRNA
Show answer & explanation

Answer: A. tRNA

Why: Transfer RNA (tRNA) carries specific amino acids to the ribosome where protein synthesis occurs.

Q15.

Lactose is found in:

  • A Milk
  • B Sugarcane
  • C Fruits
  • D Honey
Show answer & explanation

Answer: A. Milk

Why: Lactose (milk sugar) is the disaccharide present in milk.

Q16.

Which element is present in proteins but NOT in carbohydrates or fats?

  • A Nitrogen
  • B Carbon
  • C Hydrogen
  • D Oxygen
Show answer & explanation

Answer: A. Nitrogen

Why: Proteins contain nitrogen (in amino groups) in addition to C, H, and O found in all three macromolecules.

Q17.

The storage form of glucose in animals is:

  • A Glycogen
  • B Starch
  • C Cellulose
  • D Maltose
Show answer & explanation

Answer: A. Glycogen

Why: Animals store glucose as glycogen, mainly in the liver and muscles.

Q18.

Cellulose is a structural component of:

  • A Plant cell walls
  • B Animal cell membranes
  • C Animal bones
  • D Bacterial cell walls
Show answer & explanation

Answer: A. Plant cell walls

Why: Cellulose provides structural rigidity to plant cell walls.

Q19.

Which of the following is NOT a monosaccharide?

  • A Sucrose
  • B Glucose
  • C Fructose
  • D Galactose
Show answer & explanation

Answer: A. Sucrose

Why: Sucrose is a disaccharide (glucose + fructose); the others are monosaccharides.

Q20.

Haemoglobin is a protein that contains which metal ion?

  • A Iron (Fe<sup>2+</sup>)
  • B Copper (Cu<sup>2+</sup>)
  • C Zinc (Zn<sup>2+</sup>)
  • D Magnesium (Mg<sup>2+</sup>)
Show answer & explanation

Answer: A. Iron (Fe<sup>2+</sup>)

Why: Haemoglobin contains iron (Fe<sup>2+</sup>) in its haem group, which binds oxygen.

Medium - 20 questions

Q21.

What is the primary structure of a protein?

  • A Sequence of amino acids in the polypeptide chain
  • B The regular coiling pattern formed by hydrogen bonds along the backbone
  • C The regular pleated pattern formed between adjacent backbone strands
  • D The overall compact 3D shape stabilised by multiple bond types
Show answer & explanation

Answer: A. Sequence of amino acids in the polypeptide chain

Why: Primary structure is the linear sequence of amino acids linked by peptide bonds.

Q22.

Which forces stabilise the alpha-helix secondary structure of proteins?

  • A Hydrogen bonds between NH and C=O groups
  • B Covalent disulfide bonds between cysteine side chains
  • C Ionic bonds between charged side chain residues
  • D Weak van der Waals forces between nonpolar side chains
Show answer & explanation

Answer: A. Hydrogen bonds between NH and C=O groups

Why: The alpha-helix is stabilised by intramolecular hydrogen bonds between the backbone NH and C=O.

Q23.

The Chargaff rule states that in DNA:

  • A [A]=[T] and [G]=[C]
  • B [A]=[G] and [T]=[C]
  • C [A]+[T]=[G]+[C]
  • D All bases are equal
Show answer & explanation

Answer: A. [A]=[T] and [G]=[C]

Why: Chargaff's rule: adenine pairs with thymine and guanine pairs with cytosine; so [A]=[T] and [G]=[C].

Q24.

What type of bond connects nucleotides in a DNA strand?

  • A Phosphodiester bond
  • B Glycosidic bond
  • C Peptide bond
  • D Hydrogen bond
Show answer & explanation

Answer: A. Phosphodiester bond

Why: Nucleotides in a polynucleotide chain are linked by phosphodiester bonds (3'-5' linkage).

Q25.

Which sugar is present in RNA?

  • A Ribose
  • B Deoxyribose
  • C Glucose
  • D Fructose
Show answer & explanation

Answer: A. Ribose

Why: RNA contains ribose sugar; DNA contains deoxyribose (lacking the 2'-OH group).

Q26.

Enzymes are biological catalysts that are primarily:

  • A Proteins
  • B Lipids
  • C Carbohydrates
  • D Nucleic acids
Show answer & explanation

Answer: A. Proteins

Why: Most enzymes are proteins; some RNA molecules with catalytic activity are called ribozymes.

Q27.

The region of an enzyme where substrate binds is called the:

  • A Active site
  • B Allosteric site
  • C Coenzyme binding site
  • D Inhibitor site
Show answer & explanation

Answer: A. Active site

Why: The active site is the specific region of an enzyme that binds the substrate and catalyses the reaction.

Q28.

Reducing sugars give a positive test with:

  • A Fehling's solution
  • B Iodine solution
  • C Ninhydrin
  • D Biuret reagent
Show answer & explanation

Answer: A. Fehling's solution

Why: Reducing sugars (those with free aldehyde or keto groups) reduce Fehling's solution to Cu<sub>2</sub>O (brick-red).

Q29.

Which test is used to detect proteins?

  • A Biuret test
  • B Fehling's test
  • C Iodine test
  • D Tollens' test
Show answer & explanation

Answer: A. Biuret test

Why: The Biuret test detects peptide bonds; proteins give a violet/purple colour with Cu<sup>2+</sup> in alkaline solution.

Q30.

Starch gives a blue-black colour with:

  • A Iodine solution
  • B Fehling's solution
  • C Biuret reagent
  • D NaOH
Show answer & explanation

Answer: A. Iodine solution

Why: Iodine gets trapped in the helical structure of amylose in starch, giving the characteristic blue-black colour.

Q31.

Glycine is the simplest amino acid because:

  • A Its R group is just a hydrogen atom
  • B It has no carboxyl group in standard practice
  • C It has no amino group under most conditions encountered
  • D It is non-polar as frequently observed in practice
Show answer & explanation

Answer: A. Its R group is just a hydrogen atom

Why: Glycine has H as its side chain (R group), making it the smallest and simplest amino acid.

Q32.

Which amino acids form disulfide bridges in proteins?

  • A Two cysteine residues
  • B Two glycine residues
  • C Lysine and aspartate
  • D Serine and threonine
Show answer & explanation

Answer: A. Two cysteine residues

Why: Disulfide bonds (S-S) form between the -SH groups of two cysteine residues and stabilise tertiary structure.

Q33.

Denaturation of a protein involves:

  • A Loss of 3D structure while primary structure remains intact
  • B Hydrolysis of the peptide bonds linking adjacent amino acids
  • C Formation of new covalent bonds within the polypeptide chain
  • D Reduction of the protein's peptide carbonyl groups
Show answer & explanation

Answer: A. Loss of 3D structure while primary structure remains intact

Why: Denaturation disrupts secondary, tertiary, and quaternary structures without breaking peptide bonds.

Q34.

Maltose is a disaccharide formed by:

  • A Two glucose units linked by alpha 1,4-glycosidic bond
  • B Glucose and fructose joined by an alpha,beta 1,2-glycosidic bond
  • C Glucose and galactose joined by a beta 1,4-glycosidic bond
  • D Two fructose units joined by a beta 2,1-glycosidic bond
Show answer & explanation

Answer: A. Two glucose units linked by alpha 1,4-glycosidic bond

Why: Maltose is formed from two glucose units joined by an alpha-1,4 glycosidic bond.

Q35.

Which vitamin is involved in blood clotting?

  • A Vitamin K
  • B Vitamin C
  • C Vitamin B12
  • D Vitamin E
Show answer & explanation

Answer: A. Vitamin K

Why: Vitamin K is essential for the synthesis of clotting factors (e.g., prothrombin).

Q36.

What is the role of NAD+ in metabolism?

  • A Electron/hydrogen carrier in oxidation-reduction reactions
  • B A phospholipid component of the cell membrane bilayer
  • C A high-energy phosphate storage molecule like ATP
  • D An enzyme that excises damaged bases from DNA
Show answer & explanation

Answer: A. Electron/hydrogen carrier in oxidation-reduction reactions

Why: NAD+ (nicotinamide adenine dinucleotide) accepts electrons/hydrogen in metabolic oxidation reactions.

Q37.

Which part of the amino acid determines its properties?

  • A R group (side chain)
  • B Amino group
  • C Carboxyl group
  • D Alpha carbon
Show answer & explanation

Answer: A. R group (side chain)

Why: The R group (side chain) is unique to each amino acid and determines its chemical and physical properties.

Q38.

Lipids are not polymers because:

  • A They are joined by ester bonds not polymerised like polysaccharides; no repeating monomer units
  • B Their fatty acid chains contain no carbon-carbon bonds capable of linking units together
  • C They are completely insoluble in water and in every organic solvent tested
  • D Their individual molecular weight is far too low to ever form a repeating chain
Show answer & explanation

Answer: A. They are joined by ester bonds not polymerised like polysaccharides; no repeating monomer units

Why: Fats are triesters of glycerol and fatty acids, not true polymers made of repeating identical monomers.

Q39.

The Haworth projection represents:

  • A Cyclic form of carbohydrates
  • B Amino acid structure in many documented cases
  • C DNA base pairing according to conventional understanding
  • D Lipid bilayer in routine practice
Show answer & explanation

Answer: A. Cyclic form of carbohydrates

Why: Haworth projections show the ring (cyclic hemiacetal) forms of monosaccharides like glucose.

Q40.

Insulin is a hormone that is chemically a:

  • A Protein (polypeptide)
  • B Lipid overall in most cases
  • C Carbohydrate under typical conditions
  • D Nucleic acid according to standard textbooks
Show answer & explanation

Answer: A. Protein (polypeptide)

Why: Insulin is a peptide hormone made of two polypeptide chains linked by disulfide bonds.

Hard - 20 questions

Q41.

Which of the following is an essential amino acid?

  • A Lysine
  • B Glycine
  • C Alanine
  • D Glutamine
Show answer & explanation

Answer: A. Lysine

Why: Essential amino acids cannot be synthesised by the human body and must be obtained from diet. Lysine is one of the nine essential amino acids.

Q42.

The anomeric carbon in glucose is:

  • A C-1 (the aldehyde carbon in the open chain)
  • B C-2, the carbon bearing the secondary hydroxyl group
  • C C-3, the central carbon of the pyranose ring
  • D C-6, the primary alcohol carbon outside the ring
Show answer & explanation

Answer: A. C-1 (the aldehyde carbon in the open chain)

Why: The anomeric carbon (C-1 in aldoses) is the one that forms the new chiral centre when the ring closes.

Q43.

Alpha-D-glucose and beta-D-glucose are:

  • A Anomers (differ at the anomeric carbon)
  • B Enantiomers, being exact mirror images of each other
  • C Diastereomers differing in configuration at every chiral centre
  • D Constitutional isomers with different connectivity of atoms
Show answer & explanation

Answer: A. Anomers (differ at the anomeric carbon)

Why: Alpha and beta glucose differ only in the configuration at C-1 (anomeric carbon) and are called anomers.

Q44.

In the beta-pleated sheet, adjacent polypeptide chains are held by:

  • A Intermolecular hydrogen bonds between backbone groups
  • B Disulfide bonds formed between adjacent cysteine residues
  • C Ionic bonds between oppositely charged side chains
  • D Hydrophobic interactions between nonpolar side chains
Show answer & explanation

Answer: A. Intermolecular hydrogen bonds between backbone groups

Why: Beta-sheets are stabilised by hydrogen bonds between NH and C=O groups on adjacent parallel or antiparallel chains.

Q45.

Mutation in DNA results from:

  • A Change in base sequence
  • B Change in sugar
  • C Loss of phosphate
  • D Denaturation
Show answer & explanation

Answer: A. Change in base sequence

Why: A mutation is a permanent change in the nucleotide sequence of DNA, which can alter the protein encoded.

Q46.

Which enzyme catalyses the formation of peptide bonds during translation?

  • A Peptidyl transferase (part of the ribosome)
  • B DNA polymerase, which extends a nucleotide strand during replication
  • C RNA polymerase, which synthesises mRNA from a DNA template
  • D Topoisomerase, which relieves supercoiling tension in DNA
Show answer & explanation

Answer: A. Peptidyl transferase (part of the ribosome)

Why: Peptidyl transferase, a ribozyme activity of the ribosomal RNA, catalyses peptide bond formation during translation.

Q47.

What is the isoelectric point (pI) of an amino acid?

  • A The pH at which the amino acid has no net charge (zwitterion)
  • B The pH at which the amino acid is fully protonated on both ends
  • C The pKa value of the carboxyl group alone
  • D The pH at which the amino acid shows maximum aqueous solubility
Show answer & explanation

Answer: A. The pH at which the amino acid has no net charge (zwitterion)

Why: At the isoelectric point, the amino acid exists as a neutral zwitterion with equal positive and negative charges.

Q48.

Nucleoside differs from nucleotide in that nucleoside:

  • A Lacks the phosphate group
  • B Lacks the sugar according to most researchers
  • C Lacks the base in the majority of cases studied
  • D Is a polymer as widely reported
Show answer & explanation

Answer: A. Lacks the phosphate group

Why: A nucleoside = base + sugar; a nucleotide = base + sugar + phosphate.

Q49.

Which type of RNA has the shortest lifespan?

  • A mRNA
  • B tRNA
  • C rRNA
  • D snRNA
Show answer & explanation

Answer: A. mRNA

Why: mRNA is highly unstable and has a short lifespan as it encodes transient instructions for protein synthesis.

Q50.

The glycosidic bond in cellulose is:

  • A Beta-1,4 glycosidic bond
  • B Alpha-1,4 glycosidic bond
  • C Alpha-1,6 glycosidic bond
  • D Beta-1,6 glycosidic bond
Show answer & explanation

Answer: A. Beta-1,4 glycosidic bond

Why: Cellulose is formed from beta-D-glucose units linked by beta-1,4 glycosidic bonds, creating rigid linear chains.

Q51.

Which lipoprotein carries cholesterol from tissues back to the liver?

  • A HDL
  • B LDL
  • C VLDL
  • D Chylomicron
Show answer & explanation

Answer: A. HDL

Why: HDL (high-density lipoprotein) is the 'good' cholesterol carrier that transports cholesterol to the liver for processing.

Q52.

Competitive inhibitors of enzymes:

  • A Bind to the active site and compete with substrate
  • B Bind irreversibly and permanently inactivate the enzyme
  • C Unfold the enzyme's tertiary structure, destroying activity
  • D Raise the maximum velocity Vmax while leaving Km unchanged
Show answer & explanation

Answer: A. Bind to the active site and compete with substrate

Why: Competitive inhibitors resemble the substrate and compete for the active site; they increase apparent Km but not Vmax.

Q53.

Zwitterion formation in amino acids occurs because:

  • A The amino group accepts a proton from the carboxyl group intramolecularly
  • B An external acid molecule donates a proton to the amino group in standard practice
  • C The hydrophobic R group ionises under physiological pH under most conditions encountered
  • D Surrounding water molecules donate protons to both ends as frequently observed in practice
Show answer & explanation

Answer: A. The amino group accepts a proton from the carboxyl group intramolecularly

Why: In a zwitterion, the -COOH donates a proton to the -NH<sub>2</sub> group, giving -COO- and -NH<sub>3</sub><sup>+</sup>.

Q54.

Which of the following correctly describes the B-form of DNA?

  • A Right-handed double helix, 10 base pairs per turn, major and minor grooves
  • B Left-handed double helix with 12 base pairs per turn (Z-DNA form) in many documented cases
  • C A single-stranded structure lacking complementary base pairing according to conventional understanding
  • D A right-handed helix with 14 base pairs per turn in routine practice
Show answer & explanation

Answer: A. Right-handed double helix, 10 base pairs per turn, major and minor grooves

Why: The B-form (Watson-Crick form) of DNA is a right-handed helix with 10 base pairs per turn and distinct major and minor grooves.

Q55.

Enzyme activity is maximum at the optimum temperature because:

  • A Activation energy is minimum and protein structure is intact
  • B All available substrate molecules are consumed simultaneously
  • C Competitive inhibitors are completely absent from the mixture
  • D The surrounding pH is held exactly neutral at that temperature
Show answer & explanation

Answer: A. Activation energy is minimum and protein structure is intact

Why: At the optimum temperature, enough thermal energy exists for reactions but the enzyme is not yet denatured.

Q56.

Which purine base pairs with thymine in DNA?

  • A Adenine
  • B Guanine
  • C Cytosine
  • D Uracil
Show answer & explanation

Answer: A. Adenine

Why: Adenine (a purine) pairs with thymine via two hydrogen bonds; guanine pairs with cytosine via three hydrogen bonds.

Q57.

Which level of protein structure is disrupted by reducing agents (breaking S-S bonds)?

  • A Quaternary/Tertiary (disulfide bonds in tertiary structure)
  • B Primary structure, since the amino acid sequence itself is cleaved
  • C Secondary structure, since the alpha-helix hydrogen bonds break
  • D Primary sequence, since the peptide backbone is hydrolysed
Show answer & explanation

Answer: A. Quaternary/Tertiary (disulfide bonds in tertiary structure)

Why: Disulfide bonds (covalent S-S) contribute to tertiary and quaternary structure; reducing agents cleave them.

Q58.

The lock-and-key model of enzyme action proposes:

  • A Substrate shape exactly fits the rigid active site
  • B The enzyme changes shape on substrate binding
  • C Multiple substrates share one active site
  • D The substrate changes shape
Show answer & explanation

Answer: A. Substrate shape exactly fits the rigid active site

Why: Lock-and-key model (Fischer): the enzyme has a rigid complementary shape to the substrate, like a lock and key.

Q59.

Which amino acid is responsible for the UV absorption of proteins at 280 nm?

  • A Tryptophan (and tyrosine)
  • B Glycine, due to its small aliphatic side chain absorbing strongly
  • C Alanine, due to its methyl side chain's conjugated system
  • D Lysine, due to the aromatic character of its amino side chain
Show answer & explanation

Answer: A. Tryptophan (and tyrosine)

Why: Aromatic amino acids tryptophan and tyrosine absorb UV light at ~280 nm due to their pi electron systems.

Q60.

In gel electrophoresis of DNA, smaller fragments migrate:

  • A Faster toward the positive electrode
  • B Slower
  • C In random directions
  • D Toward the negative electrode
Show answer & explanation

Answer: A. Faster toward the positive electrode

Why: DNA is negatively charged and migrates toward the positive pole; smaller fragments migrate faster through the gel matrix.