In CFT, the crystal field stabilisation energy (CFSE) for d 6 high spin in octahedral field is:

Zero, since the high-spin d 6 arrangement gives no net stabilisation

-1.2 Delta_o, the value corresponding instead to a d 3 configuration

-2.4 Delta_o, the value corresponding instead to a low-spin d 6 configuration

In CFT, the crystal field stabilisation energy (CFSE) for d 6…

Answer: -0.4 Delta_o (4 in t_2g × -0.4 + 2 in eg × +0.6 = -1.6 + 1.2 = -0.4 Delta_o).

A -0.4 Delta_o (4 in t_2g × -0.4 + 2 in eg × +0.6 = -1.6 + 1.2 = -0.4 Delta_o)
B Zero, since the high-spin d⁶ arrangement gives no net stabilisation
C -1.2 Delta_o, the value corresponding instead to a d³ configuration
D -2.4 Delta_o, the value corresponding instead to a low-spin d⁶ configuration

Correct answer: A. -0.4 Delta_o (4 in t_2g × -0.4 + 2 in eg × +0.6 = -1.6 + 1.2 = -0.4 Delta_o)

Explanation: d⁶ high spin: t2g4 eg2. CFSE = 4(-0.4) + 2(+0.6) = -1.6 + 1.2 = -0.4 Delta_o.

The three common coordination geometries: octahedral (6 ligands), tetrahedral (4 ligands), and square planar (4 ligands in one plane).

Concept context

Study of compounds where a central metal atom is bonded to surrounding ligands. Covers nomenclature, types of isomerism, bonding theories (VBT, CFT), and applications in medicine, photography, and industry.

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In CFT, the crystal field stabilisation energy (CFSE) for d6 high spin in octahedral field is:

Concept context

More Coordination Compounds questions

In CFT, the crystal field stabilisation energy (CFSE) for d⁶ high spin in octahedral field is: