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Given lambda° values (S cm2 mol-1): HCl = 426, CH3COONa = 91, NaCl = 126. The lambda° for acetic acid is:

Answer: 391 S cm2 mol-1.

  • A 217 S cm2 mol-1
  • B 300 S cm2 mol-1
  • C 391 S cm2 mol-1
  • D 461 S cm2 mol-1

Correct answer: C. 391 S cm2 mol-1

Explanation: By Kohlrausch law, lambda°(CH3COOH) = lambda°(HCl) + lambda°(CH3COONa) - lambda°(NaCl) = 426 + 91 - 126 = 391.

ZnSO4 solutionCuSO4 solutionZnCuAnode (-)Cathode (+)oxidationreductionVSalt bridgee- flow

In a Daniell cell, electrons flow externally from the zinc anode (oxidation) through the voltmeter to the copper cathode (reduction), while the salt bridge completes the circuit.

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