Zaymiey

📐 Mathematics  ·  Binomial Theorem  ·  JEE

Find the value of (√2 + 1)⁵ + (√2 - 1)⁵.

Answer: 58√2.

  • A 82√2
  • B 82
  • C 58
  • D 58√2

Correct answer: D. 58√2

Explanation: Using (a+b)5 + (a-b)5 = 2[5C0 a5 + 5C2 a3 b2 + 5C4 a b4]. With a=sqrt(2), b=1: 2[4sqrt(2)+10*2sqrt(2)+5sqrt(2)] = 2[4+20+5]sqrt(2) = 58sqrt(2).

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →