Zaymiey

📐 Mathematics  ·  Binomial Theorem  ·  JEE

The coefficient of x⁴ in the expansion of (1 + x)ⁿ(1 + x)ⁿ = (1+x)²ⁿ is:

Answer: (2n)C4.

  • A (2n)C4
  • B nC4 + nC2 + nC0
  • C nC2 × nC2
  • D (nC4)²

Correct answer: A. (2n)C4

Explanation: Combine bases: (1+x)ⁿ·(1+x)ⁿ=(1+x)2n. General term: T(r+1)=C(2n,r)xʳ. For the x⁴ term set r=4: coefficient is C(2n,4)=(2n)C4. Convolution of individual terms is equivalent but the merged form gives this directly.

Pascal's Triangle: Binomial Coefficients11112113311464115101051n=0n=1n=2n=3n=4n=5Each entry = sum of the two entries diagonally above it (Pascal's identity); row n gives nC0...nCn

Row n of Pascal's triangle gives the coefficients nC0, nC1, ..., nCn for the expansion of (a+b)ⁿ; each number is the sum of the two numbers diagonally above it, a direct visual proof of the identity nCr = (n-1)C(r-1) + (n-1)Cr.

Concept context

Expansion of (a+b) n , general term, middle term, binomial coefficients, and greatest term

Read the full Binomial Theorem notes →