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📐 Mathematics  ·  Conic Sections  ·  JEE

For an ellipse x2/a2 + y2/b2 = 1 with a > b, the relationship between a, b, and c (distance to focus) is:

Answer: c2 = a2 - b2.

  • A c2 = a2 + b2
  • B c2 = a2 - b2
  • C c2 = b2 - a2
  • D c = a + b

Correct answer: B. c2 = a2 - b2

Explanation: For an ellipse, c2 = a2 - b2, since the foci lie inside the ellipse.

The Four Conics by EccentricityCircle (e=0)Ellipse (0<e<1)Parabola (e=1)Hyperbola (e>1)

All four conics form a single family distinguished only by eccentricity: a circle is the most "closed" (e=0), an ellipse is an elongated closed curve, a parabola is the borderline open curve (e=1), and a hyperbola has two separate open branches (e>1).

Concept context

Study circles, parabolas, ellipses, and hyperbolas as curves formed by intersecting a plane with a double cone, with their standard equations and key properties.

Read the full Conic Sections notes →