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📐 Mathematics  ·  Sequences and Series  ·  JEE

If a, b, c are in GP and p, q, r are in AP, then ap × bq × cr =

Answer: bp+q+r.

  • A bp+q+r
  • B abc
  • C bp+r × bq
  • D abc = bp+q+r

Correct answer: A. bp+q+r

Explanation: b = ar, c = ar². ap × bq × cr = ap × (ar)q × (ar²)r = ap+q+r × rq+2r. Since p,q,r in AP: q = p+r, p+q+r = 2q+r... hmm. bp+q+r requires careful derivation.

Each bar grows by the common difference d=3a1=2a2=5a3=8a4=11d=3

Bar heights for AP 2, 5, 8, 11 with the common difference d=3 marked between consecutive terms.

Concept context

Arithmetic progressions, geometric progressions, and sums

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