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📐 Mathematics  ·  Vector Algebra  ·  JEE

The parallelogram law of vector addition: |a + b|2 + |a - b|2 =

Answer: 2(|a|2 + |b|2).

  • A 2|a|2
  • B 2|b|2
  • C 2(|a|2 + |b|2)
  • D 4(|a|2 + |b|2)

Correct answer: C. 2(|a|2 + |b|2)

Explanation: Parallelogram law of cosines: |a+b|2 + |a-b|2 = 2(|a|2 + |b|2). The sum of squares of diagonals equals twice the sum of squares of the sides.

xya (4,1)b (2,3)a + b (6,4)

Triangle law of vector addition: placing vector b at the head of vector a, the diagonal from the start to the final head gives the resultant a + b.

Concept context

Vectors, dot product, cross product, and geometric applications

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