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⚛️ Physics  ·  Alternating Current  ·  NEET & JEE

Resonant frequency of an LC circuit with L=0.1 mH and C=0.1 microF:

Answer: 159 kHz.

  • A 50 kHz
  • B 100 kHz
  • C 159 kHz
  • D 1000 kHz

Correct answer: C. 159 kHz

Explanation: f0 = 1/(2pi sqrt(LC)) = 1/(2pi sqrt(10-4 x 10-7)) = 1/(2pi x 10-5.5) = 1/(2pi x 3.16 x 10-6) = 106/(2pi x 3.16) = 159 kHz.

V and I Phase Relationships in AC CircuitsPure Inductor: I lags V by 90°VIPure Capacitor: I leads V by 90°VIMemory aid "ELI the ICE man": in an inductor (L) E(V) leads I; in a capacitor (C) I leads E(V)For a pure resistor, V and I stay perfectly in phase (no lag or lead at all)

In a pure inductor the current lags the voltage by 90° (energy is briefly stored in the magnetic field before current responds); in a pure capacitor the current leads the voltage by 90° (current must flow to build up charge before voltage rises) - the mnemonic "ELI the ICE man" keeps these straight.

Concept context

AC circuits, impedance, LCR series circuit, resonance, transformers, and power factor.

Read the full Alternating Current notes →