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⚛️ Physics  ·  Current Electricity  ·  NEET & JEE

Heat developed in a resistor R1 in series with R2 (R1:R2 = 1:2) in time t:

Answer: H1:H2 = 1:2.

  • A H1:H2 = 1:2
  • B H1:H2 = 2:1
  • C H1:H2 = 1:4
  • D H1:H2 = 4:1

Correct answer: A. H1:H2 = 1:2

Explanation: In series, same current. H = I2 R t. H1/H2 = R1/R2 = 1/2.

SeriesbatteryR1R2I (same in R1, R2)ParallelbatteryR1R2I1I2

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

Read the full Current Electricity notes →