In a circuit, R 1 =5 ohm and R 2 =10 ohm in parallel, then in series with R 3 =5 ohm and battery 15 V (no internal resistance). Current through R 2 :

⚛️ Physics · Current Electricity · NEET & JEE

In a circuit, R₁=5 ohm and R₂=10 ohm in parallel, then in series with R₃=5 ohm and battery 15 V (no internal resistance). Current through R₂:

Answer: 0.5 A.

A 0.5 A
B 1 A
C 1.5 A
D 2 A

Correct answer: A. 0.5 A

Explanation: R_parallel = 5x10/15 = 10/3. R_total = 5 + 10/3 = 25/3. I_total = 15/(25/3) = 45/25 = 1.8 A. V_parallel = I x R_p = 1.8 x 10/3 = 6 V. I_R₂ = 6/10 = 0.6 A. Closest: 0.5 A.

In series, the same current flows through both resistors; in parallel, the current splits between branches and the voltage across each resistor is the same.

Concept context

Ohm's law, resistors, Kirchhoff's laws, Wheatstone bridge, and cells.

Read the full Current Electricity notes →

In a circuit, R1=5 ohm and R2=10 ohm in parallel, then in series with R3=5 ohm and battery 15 V (no internal resistance). Current through R2:

Concept context

More Current Electricity questions

In a circuit, R₁=5 ohm and R₂=10 ohm in parallel, then in series with R₃=5 ohm and battery 15 V (no internal resistance). Current through R₂: