In a network of resistors, we can use superposition. Current due to source E 1 alone (E 2 removed/short-circuited) in a branch is I 1 . Due to E 2 alone it is I 2 . Actual current:

Question

Accepted Answer

I 1 + I 2 (algebraically, respecting direction)

Answer

I 1 + I 2 usually, regardless of the direction each current actually flows

Answer

I 1 x I 2 , multiplying the two branch currents together

Answer

max(I 1 , I 2 ), taking mainly whichever current is larger in magnitude

In a network of resistors, we can use superposition. Current due to source E₁ alone (E₂ removed/short-circuited) in a branch is I₁. Due to E₂ alone it is I₂. Actual current:

Concept context

In a network of resistors, we can use superposition. Current due to source E1 alone (E2 removed/short-circuited) in a branch is I1. Due to E2 alone it is I2. Actual current:

Concept context

More Current Electricity questions

In a network of resistors, we can use superposition. Current due to source E₁ alone (E₂ removed/short-circuited) in a branch is I₁. Due to E₂ alone it is I₂. Actual current: