Zaymiey

⚛️ Physics  ·  Gravitation  ·  NEET & JEE

The escape velocity from Earth is 11.2 km/s. If a body is projected at 22.4 km/s, its speed far away from Earth (ignoring other bodies) is about:

Answer: 19.4 km/s.

  • A 22.4 km/s
  • B 11.2 km/s
  • C 19.4 km/s
  • D 33.6 km/s

Correct answer: C. 19.4 km/s

Explanation: Energy conservation: v∞ = √(v2 - ve2) = √(22.42 - 11.22) = √376.3 ≈ 19.4 km/s.

Variation of g with Height and Depthgg_surfaceAbove surface: g ∝ 1/r² (falls off curving down)Below surface: g ∝ r (falls off LINEARLY)Earth's surface (r = R)centre (r=0): g=0g is MAXIMUM exactly at the surface - it decreases in both directions, but by different laws

g is maximum at Earth's surface; going up, it falls off as 1/r² (inverse-square); going down, it falls off linearly with depth (since only the mass enclosed within radius r contributes), reaching zero at the centre.

Concept context

Universal gravitation, orbital mechanics, gravitational potential, and escape velocity.

Read the full Gravitation notes →