Answer: Tmax/(M+m) - g.
- A Tmax/(M+m) - g
- B Tmax/M - g
- C Tmax/m - g
- D Tmax/(M-m) - g
Correct answer: A. Tmax/(M+m) - g
Explanation: Tension supports both: T = (M+m)(g+a). Max a = Tmax/(M+m) - g.
Free-body diagram of a block on an incline: weight (mg) resolves into mg sinθ along the slope and mg cosθ into the slope, balanced by the normal force N and friction f.
Concept context
Newton's three laws, friction, circular motion, and free body diagrams.