In a hydraulic press with areas A 1 = 10 cm² and A 2 = 1000 cm², a force of 100 N on the small piston produces a force on the large piston of:

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In a hydraulic press with areas A₁ = 10 cm² and A₂ = 1000 cm², a force of 100 N on the small piston produces a force on the large piston of:

Answer: 10,000 N.

A 10,000 N
B 1 N
C 100 N
D 1000 N

Correct answer: A. 10,000 N

Explanation: Pascal's law: F₁/A₁ = F₂/A₂ (pressure transmitted). F₂ = F₁ × A₂/A₁ = 100 × 1000/10 = 10,000 N. This mechanical advantage is the basis of hydraulic machines.

Since the same volume of fluid must pass every cross-section per second (continuity), the fluid speeds up where the pipe narrows; Bernoulli's equation then says this faster-moving fluid has lower pressure - the principle behind a venturi meter and an aircraft wing's lift.

Concept context

Pressure, buoyancy, Bernoulli equation, viscosity, and surface tension.

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In a hydraulic press with areas A1 = 10 cm² and A2 = 1000 cm², a force of 100 N on the small piston produces a force on the large piston of:

Concept context

More Mechanical Properties of Fluids questions

In a hydraulic press with areas A₁ = 10 cm² and A₂ = 1000 cm², a force of 100 N on the small piston produces a force on the large piston of: