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⚛️ Physics  ·  Mechanical Properties of Fluids  ·  NEET & JEE

Two holes are at depths h1 and h2 from the water surface of a tank. Their ranges on the ground are equal. The relationship is:

Answer: h1 + h2 = H (total tank height).

  • A h1 + h2 = H (total tank height)
  • B h1 = h2, meaning the two holes are at the same depth
  • C h1 × h2 = H², an incorrect product relation with the tank height
  • D h1 = 2h2, an arbitrary fixed ratio between the two depths

Correct answer: A. h1 + h2 = H (total tank height)

Explanation: Range = 2√(h(H-h)). For equal ranges: h1(H-h1) = h2(H-h2). This holds when h1 and h2 are symmetric about H/2, i.e., h1 + h2 = H.

Continuity Equation: Narrow Pipe → Faster FlowA₁, v₁ (wide, slow)A₂, v₂ (narrow, fast)A₁v₁ = A₂v₂ (continuity)Smaller area → higher speed → (by Bernoulli) LOWER pressure

Since the same volume of fluid must pass every cross-section per second (continuity), the fluid speeds up where the pipe narrows; Bernoulli's equation then says this faster-moving fluid has lower pressure - the principle behind a venturi meter and an aircraft wing's lift.

Concept context

Pressure, buoyancy, Bernoulli equation, viscosity, and surface tension.

Read the full Mechanical Properties of Fluids notes →