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⚛️ Physics  ·  Mechanical Properties of Fluids  ·  NEET & JEE

Two soap bubbles of radii r1 and r2 are connected by a tube. If r1 > r2, what happens?

Answer: Smaller bubble (r2) shrinks and larger (r1) grows.

  • A Smaller bubble (r2) shrinks and larger (r1) grows
  • B The larger bubble shrinks while the smaller one grows instead
  • C Both bubbles settle to exactly the same final equilibrium radius
  • D Neither bubble's size changes once they are connected by the tube

Correct answer: A. Smaller bubble (r2) shrinks and larger (r1) grows

Explanation: Excess pressure in a soap bubble = 4T/r. The smaller bubble (r2) has higher pressure than the larger one (r1). Air flows from smaller to larger. The smaller bubble shrinks.

Continuity Equation: Narrow Pipe → Faster FlowA₁, v₁ (wide, slow)A₂, v₂ (narrow, fast)A₁v₁ = A₂v₂ (continuity)Smaller area → higher speed → (by Bernoulli) LOWER pressure

Since the same volume of fluid must pass every cross-section per second (continuity), the fluid speeds up where the pipe narrows; Bernoulli's equation then says this faster-moving fluid has lower pressure - the principle behind a venturi meter and an aircraft wing's lift.

Concept context

Pressure, buoyancy, Bernoulli equation, viscosity, and surface tension.

Read the full Mechanical Properties of Fluids notes →