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⚛️ Physics  ·  Thermal Properties of Matter  ·  NEET & JEE

A black body radiates energy at a rate E1 at temperature T. If the temperature is doubled, the new rate of radiation E2 in terms of E1 is:

Answer: 16E1.

  • A 2E1
  • B 4E1
  • C 8E1
  • D 16E1

Correct answer: D. 16E1

Explanation: By Stefan-Boltzmanns law, E ∝ T⁴. Doubling T increases E by a factor of 2⁴ = 16, so E2 = 16E1.

Heating Curve: Ice → Water → SteamHeat added (Q)T (°C)ice warms (-ve→0°C)melting (0°C, latent heat)water warms (0→100°C)boiling (100°C, latent heat)FLAT regions = phase change (all heat goes into breaking bonds, NOT raising temperature)

During a phase change (melting or boiling), temperature stays constant while heat is absorbed entirely as latent heat (Q=mL); temperature only rises again once the substance is fully in its new phase.

Concept context

Temperature scales, thermal expansion, calorimetry, and the three modes of heat transfer including radiation laws.

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