Answer: 25/3.
- A 2
- B 23/5
- C 25/3
- D 3/5
Correct answer: C. 25/3
Explanation: PVgamma = constant. P1 V15/3 = P2 V25/3. V25/3 = (P1/P2) V15/3 = 2 V15/3. V2 = 23/5 V1. Answer: 23/5.
The Carnot cycle alternates two isothermal steps (heat absorbed at TH, released at TC) with two adiabatic steps (no heat exchange); the enclosed loop area equals the net work output, and η = 1−TC/TH is the maximum possible efficiency between those two temperatures.
Concept context
Laws of thermodynamics, heat engines, entropy, and gas processes.