The frequency of vibration of a liquid drop is assumed to depend only on the surface tension S, the density and the radius r. Dimensional analysis gives the frequency proportional to:

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The frequency of vibration of a liquid drop is assumed to depend only on the surface tension S, the density ρ and the radius r. Dimensional analysis gives the frequency proportional to:

Answer: √(S / ρr³).

A √(Sρ / r³)
B √(ρr³ / S)
C √(S / ρr)
D √(S / ρr³)

Correct answer: D. √(S / ρr³)

Explanation: With [S] = M T^-2, [ρ] = M L^-3, [r] = L, matching [T^-1] gives f &prop; S^1/2ρ^-1/2r^-3/2 = √(S/ρr³).

The 7 SI base units. All derived units (newton, joule, watt, volt, etc.) can be expressed as combinations of these 7 fundamental units raised to various powers.

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The frequency of vibration of a liquid drop is assumed to depend only on the surface tension S, the density &rho; and the radius r. Dimensional analysis gives the frequency proportional to:

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The frequency of vibration of a liquid drop is assumed to depend only on the surface tension S, the density ρ and the radius r. Dimensional analysis gives the frequency proportional to: