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⚛️ Physics  ·  Wave Optics  ·  NEET & JEE

Unpolarized light (I0) passes through polaroid P1, then through P2 at 30° to P1, then through P3 at 90° to P1. Final intensity is:

Answer: 3I0/16.

  • A 3I0/16
  • B I0/8
  • C I0/4
  • D I0/2

Correct answer: A. 3I0/16

Explanation: After P1: I0/2. After P2 (at 30° to P1): (I0/2)cos²(30°) = (I0/2)(3/4) = 3I0/8. P3 is at 90°-30°=60° to P2: (3I0/8)cos²(60°) = (3I0/8)(1/4) = 3I0/32.

Young's Double Slit Experimentsourceslits S₁,S₂dscreenbrightdarkPath difference at the screen determines bright (constructive, nλ) vs dark (destructive, (2n-1)λ/2) fringes

Two coherent slits S₁ and S₂ act as secondary sources; at each point on the screen, the path difference between light from S₁ and S₂ determines whether the waves arrive in phase (bright fringe) or out of phase (dark fringe), producing the characteristic alternating fringe pattern.

Concept context

Huygens principle, Young's double slit, diffraction, polarization. Essential for JEE.

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