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Isolation of Elements - Practice Questions with Answers

60 free MCQs on Isolation of Elements with worked answers and explanations. The science of extracting metals from ores and refining them for use. Covers concentration methods, reduction techniques, refining processes, and the thermodynamic principles that govern metal extraction.

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Below are 60 practice questions on Isolation of Elements, sorted Easy → Hard. Tap “Show answer & explanation” under any question to check yourself. Want the full theory first? Read the Isolation of Elements notes.

Ellingham Diagram (simplified)T (°C)ΔG° (more negative ↑)CO + ½O₂ → CO₂ (carbon line)2Al + 1.5O₂ → Al₂O₃2Mg + O₂ → 2MgOcrossover: above this T, carbon reduces Al₂O₃

An Ellingham diagram plots ΔG° of oxide formation against temperature for different metals; whichever line is LOWER (more negative ΔG°) at a given temperature reduces the oxide of any metal whose line sits above it - the basis of carbon reduction (Fe, Zn) vs electrolytic reduction (Al, Mg, Na) decisions.

Easy - 20 questions

Q1.

Metallurgy is the process of:

  • A Extracting metals from their ores
  • B Manufacturing plastic in most textbook accounts
  • C Producing acids during normal conditions
  • D Making alloys mainly as generally observed
Show answer & explanation

Answer: A. Extracting metals from their ores

Why: Metallurgy encompasses all processes for extracting and refining metals from their naturally occurring ores.

Q2.

An ore is:

  • A A naturally occurring mineral from which a metal can be profitably extracted
  • B Generally any rock found in the Earth's crust regardless of metal content
  • C A largely purified metal ready for direct industrial use in typical laboratory settings
  • D Any metal compound, regardless of whether extraction is economical under usual circumstances
Show answer & explanation

Answer: A. A naturally occurring mineral from which a metal can be profitably extracted

Why: An ore is a naturally occurring rock or mineral from which a metal can be extracted economically.

Q3.

Which ore is used to extract iron?

  • A Haematite (Fe2O<sub>3</sub>)
  • B Bauxite in typical laboratory settings
  • C Galena under usual circumstances
  • D Malachite according to most researchers
Show answer & explanation

Answer: A. Haematite (Fe2O<sub>3</sub>)

Why: Haematite (Fe2O<sub>3</sub>) is the main ore of iron used in blast furnace extraction.

Q4.

Bauxite is the ore of:

  • A Aluminium
  • B Iron
  • C Copper
  • D Zinc
Show answer & explanation

Answer: A. Aluminium

Why: Bauxite (mainly Al<sub>2</sub>O<sub>3</sub>·2H<sub>2</sub>O) is the principal ore from which aluminium is extracted.

Q5.

Galena is the ore of:

  • A Lead
  • B Zinc
  • C Iron
  • D Copper
Show answer & explanation

Answer: A. Lead

Why: Galena (PbS) is the primary ore of lead.

Q6.

Sphalerite (zinc blende) is the ore of:

  • A Zinc
  • B Lead
  • C Copper
  • D Iron
Show answer & explanation

Answer: A. Zinc

Why: Sphalerite (ZnS, zinc blende) is the main ore from which zinc is extracted.

Q7.

Cuprite is the ore of:

  • A Copper
  • B Zinc
  • C Iron
  • D Nickel
Show answer & explanation

Answer: A. Copper

Why: Cuprite (Cu<sub>2</sub>O) and chalcopyrite (CuFeS2) are the main copper ores.

Q8.

The process of heating a concentrated ore strongly in the presence of air is called:

  • A Roasting
  • B Calcination
  • C Smelting
  • D Refining
Show answer & explanation

Answer: A. Roasting

Why: Roasting heats sulfide ores in excess air; sulfides are converted to oxides with SO<sub>2</sub> as a byproduct.

Q9.

Calcination involves heating the ore:

  • A In the absence of air (or limited air)
  • B In a large excess of air to fully oxidise the ore
  • C Together with water to dissolve the impurities
  • D Together with concentrated hydrochloric acid
Show answer & explanation

Answer: A. In the absence of air (or limited air)

Why: Calcination heats carbonate or hydroxide ores without air; e.g., CaCO<sub>3</sub> → CaO + CO<sub>2</sub> (limestone).

Q10.

The gangue in an ore is:

  • A The unwanted earthy impurities mixed with the ore mineral
  • B The valuable metal extracted from the mineral itself
  • C The reducing agent added during the smelting stage
  • D The slag formed later during the smelting process
Show answer & explanation

Answer: A. The unwanted earthy impurities mixed with the ore mineral

Why: Gangue is the unwanted non-metallic material (clay, sand, rock) mixed with the ore mineral.

Q11.

Flux is added in metallurgy to:

  • A React with gangue to form fusible slag that can be separated from the metal
  • B Chemically reduce the metal oxide directly to the free metal in the majority of cases studied
  • C Deliberately oxidise the molten metal during the smelting stage as widely reported
  • D Lower the overall furnace temperature needed for smelting in standard practice
Show answer & explanation

Answer: A. React with gangue to form fusible slag that can be separated from the metal

Why: Flux (e.g., limestone for silica gangue) reacts with gangue to form a low-melting slag that floats on molten metal.

Q12.

Smelting is:

  • A Reduction of metal oxide by heating with a reducing agent (e.g., coke/carbon)
  • B Direct oxidation of the raw ore prior to any reduction step under most conditions encountered
  • C Simple dissolution of the ore in a strong mineral acid as frequently observed in practice
  • D Electrolysis of the ore in aqueous solution in many documented cases according to conventional understanding
Show answer & explanation

Answer: A. Reduction of metal oxide by heating with a reducing agent (e.g., coke/carbon)

Why: Smelting uses carbon (coke) or other reducing agents to reduce metal oxides to the metal at high temperature.

Q13.

The blast furnace is used to extract:

  • A Iron from haematite
  • B Aluminium from bauxite
  • C Copper from chalcopyrite
  • D Zinc from sphalerite
Show answer & explanation

Answer: A. Iron from haematite

Why: The blast furnace reduces iron oxide (haematite/magnetite) using coke (carbon monoxide) to produce pig iron.

Q14.

In the blast furnace, the reducing agent is:

  • A Carbon monoxide (CO) formed from coke
  • B Hydrogen gas injected directly into the furnace
  • C Molten aluminium added as a reducing agent
  • D Calcium metal added as a reducing agent
Show answer & explanation

Answer: A. Carbon monoxide (CO) formed from coke

Why: CO (from coke combustion in limited air) reduces Fe2O<sub>3</sub>: Fe2O<sub>3</sub> + 3CO → 2Fe + 3CO<sub>2</sub>.

Q15.

Aluminium is extracted by:

  • A Hall-Heroult electrolytic process (electrolysis of molten Al<sub>2</sub>O<sub>3</sub> in cryolite)
  • B A blast furnace process using coke as the reducing agent in routine practice
  • C The thermite reaction run in reverse to liberate aluminium overall in most cases
  • D Simple roasting of bauxite ore in open air under typical conditions according to standard textbooks
Show answer & explanation

Answer: A. Hall-Heroult electrolytic process (electrolysis of molten Al<sub>2</sub>O<sub>3</sub> in cryolite)

Why: Al<sub>2</sub>O<sub>3</sub> is reduced electrolytically in the Hall-Heroult process: Al<sub>2</sub>O<sub>3</sub> dissolved in molten cryolite (Na3AlF6) is electrolysed.

Q16.

The Bayer process is used to:

  • A Purify bauxite to alumina (Al<sub>2</sub>O<sub>3</sub>) before electrolysis
  • B Extract iron from its oxide ore in a blast furnace
  • C Electrolytically refine impure blister copper
  • D Produce steel from pig iron in a converter
Show answer & explanation

Answer: A. Purify bauxite to alumina (Al<sub>2</sub>O<sub>3</sub>) before electrolysis

Why: Bayer process: bauxite + NaOH → NaAlO2 (sodium aluminate); filtered then precipitated to give pure Al(OH)<sub>3</sub> → Al<sub>2</sub>O<sub>3</sub> by calcination.

Q17.

Thermite welding uses the reaction:

  • A Fe2O<sub>3</sub> + 2Al → Al<sub>2</sub>O<sub>3</sub> + 2Fe (aluminium reduces iron oxide, highly exothermic)
  • B Fe + O<sub>2</sub> → Fe2O<sub>3</sub>, the simple rusting reaction of iron in air in general practice
  • C Al + H<sub>2</sub>O → Al<sub>2</sub>O<sub>3</sub> + H<sub>2</sub>, the reaction of aluminium with water as frequently described
  • D Al + Fe → alloy, a direct alloying reaction with little oxide involved
Show answer & explanation

Answer: A. Fe2O<sub>3</sub> + 2Al → Al<sub>2</sub>O<sub>3</sub> + 2Fe (aluminium reduces iron oxide, highly exothermic)

Why: The thermite reaction produces molten iron in situ; used for welding railway tracks due to the extreme localised heat.

Q18.

Zone refining is used to obtain:

  • A Very pure semiconductors (Si, Ge) by moving a molten zone through the material
  • B Crude, completely unrefined metal straight from the original smelting furnace charge
  • C Iron alloys specifically blended and cast for heavy structural construction purposes
  • D Common table salt purified by recrystallisation directly from a saturated brine solution
Show answer & explanation

Answer: A. Very pure semiconductors (Si, Ge) by moving a molten zone through the material

Why: Zone refining (zone melting) purifies metals/semiconductors by moving a molten zone; impurities concentrate in the melt and are swept to one end.

Q19.

Copper is refined by:

  • A Electrolytic refining (crude Cu anode, pure Cu cathode, CuSO<sub>4</sub> electrolyte)
  • B Simple distillation of the molten metal under vacuum in most textbook accounts
  • C Zone refining by passing a molten zone along a copper rod during normal conditions
  • D The thermite process used instead to refine iron oxide as generally observed
Show answer & explanation

Answer: A. Electrolytic refining (crude Cu anode, pure Cu cathode, CuSO<sub>4</sub> electrolyte)

Why: In electrolytic refining, Cu dissolves from the crude anode and deposits as pure Cu on the cathode; impurities collect as anode mud.

Q20.

Slag in a blast furnace is mainly:

  • A Calcium silicate (CaSiO3) formed from CaO + SiO<sub>2</sub>
  • B Pure unreacted silica left over from the original ore
  • C Iron carbide formed from excess carbon reacting with iron
  • D Carbon dioxide gas trapped within the molten iron
Show answer & explanation

Answer: A. Calcium silicate (CaSiO3) formed from CaO + SiO<sub>2</sub>

Why: Limestone (CaCO<sub>3</sub>) decomposes to CaO + CO<sub>2</sub>; CaO + SiO<sub>2</sub> (gangue) → CaSiO3 (slag), which floats on molten iron.

Medium - 20 questions

Q21.

The froth flotation process is used to concentrate:

  • A Sulfide ores (e.g., ZnS, PbS, Cu2S) using pine oil
  • B Oxide ores, which are instead concentrated by magnetic separation
  • C Carbonate ores, which are instead concentrated by gravity separation
  • D Native metals, which require no concentration step at all
Show answer & explanation

Answer: A. Sulfide ores (e.g., ZnS, PbS, Cu2S) using pine oil

Why: Froth flotation: crushed ore in water with pine oil (collector) and pine oil generates froth; sulfide mineral particles are hydrophobic and float; gangue sinks.

Q22.

In froth flotation, collectors are chemicals that:

  • A Make the ore surface hydrophobic so it attaches to air bubbles
  • B Chemically dissolve the ore particles into the surrounding water
  • C React directly with the gangue to convert it into soluble salts
  • D Generate the stable froth layer at the top of the flotation cell
Show answer & explanation

Answer: A. Make the ore surface hydrophobic so it attaches to air bubbles

Why: Collectors (e.g., xanthates, thio compounds) adsorb on the metal sulfide surface, making it hydrophobic, allowing it to attach to air bubbles and float.

Q23.

Magnetic separation is used for ores that are:

  • A Magnetic (e.g., magnetite Fe<sub>3</sub>O<sub>4</sub>) to separate from non-magnetic gangue
  • B Generally denser than the surrounding gangue material overall in most cases
  • C Sulfide ores best separated instead by froth flotation under typical conditions
  • D Carbonate ores best separated instead by gravity methods according to standard textbooks
Show answer & explanation

Answer: A. Magnetic (e.g., magnetite Fe<sub>3</sub>O<sub>4</sub>) to separate from non-magnetic gangue

Why: Magnetic ores (like magnetite) are separated from non-magnetic gangue by passing the crushed mixture over a magnetic roller.

Q24.

The Ellingham diagram helps to predict:

  • A Whether a metal oxide can be reduced by a particular reducing agent at a given temperature (comparing free energies of formation)
  • B Generally the precise characteristic colour displayed visually by each freshly purified pure metal sample in general practice
  • C Generally the overall industrial rate at which a given target metal can ultimately be extracted from its ore as frequently described
  • D Generally the aqueous solubility behaviour shown experimentally by various naturally occurring ore minerals in most textbook accounts
Show answer & explanation

Answer: A. Whether a metal oxide can be reduced by a particular reducing agent at a given temperature (comparing free energies of formation)

Why: An Ellingham diagram plots Delta_G vs T for metal oxide formation; if the reducing agent's line is below the metal oxide line, reduction is thermodynamically favourable.

Q25.

In the Ellingham diagram, the carbon line crosses the iron oxide line at about 700°C. This means:

  • A Above 700°C, carbon (coke) can reduce Fe2O<sub>3</sub> spontaneously; below, it cannot
  • B Metallic iron is instead able to reduce carbon oxides above this temperature
  • C The carbon and iron oxide lines actually never cross on the diagram
  • D Iron oxide spontaneously decomposes into free iron without any reducing agent
Show answer & explanation

Answer: A. Above 700°C, carbon (coke) can reduce Fe2O<sub>3</sub> spontaneously; below, it cannot

Why: Where the C/CO line crosses below the Fe/Fe2O<sub>3</sub> line, Delta_G for the overall reduction becomes negative; that temperature is the minimum for coke reduction of iron oxide.

Q26.

Leaching is used to concentrate:

  • A Low-grade ores by dissolving the metal selectively (e.g., gold in NaCN solution, Al<sub>2</sub>O<sub>3</sub> in NaOH)
  • B Every type of ore that exists, regardless of grade or actual metal content present during normal conditions
  • C Mainly sulfide ores, which in practice are concentrated instead by froth flotation as generally observed
  • D Mainly ores that are already high-grade and therefore need no further concentration step in typical laboratory settings
Show answer & explanation

Answer: A. Low-grade ores by dissolving the metal selectively (e.g., gold in NaCN solution, Al<sub>2</sub>O<sub>3</sub> in NaOH)

Why: Leaching dissolves the metal from the ore matrix; e.g., Bayer process (Al<sub>2</sub>O<sub>3</sub> in NaOH), cyanide leaching (Au in NaCN/O<sub>2</sub>).

Q27.

The MacArthur-Forest (cyanide) process is used for:

  • A Extracting gold (4Au + 8NaCN + O<sub>2</sub> + 2H<sub>2</sub>O → 4Na[Au(CN)2] + 4NaOH)
  • B Extracting iron from its oxide ore using a blast furnace under usual circumstances
  • C Electrolytically refining impure blister copper according to most researchers
  • D Extracting aluminium from bauxite via electrolysis in the majority of cases studied
Show answer & explanation

Answer: A. Extracting gold (4Au + 8NaCN + O<sub>2</sub> + 2H<sub>2</sub>O → 4Na[Au(CN)2] + 4NaOH)

Why: Gold dissolves in aerated dilute NaCN solution; the complex Na[Au(CN)2] is then reduced by zinc to deposit gold.

Q28.

Bessemer converter is used in:

  • A Converting pig iron to steel by blowing air through molten pig iron to oxidise impurities
  • B Producing aluminium metal from molten alumina dissolved in cryolite by electrolysis
  • C Extracting zinc metal by reducing roasted zinc oxide ore with carbon monoxide
  • D Electrolytically refining impure blister copper metal using a copper sulfate bath
Show answer & explanation

Answer: A. Converting pig iron to steel by blowing air through molten pig iron to oxidise impurities

Why: The Bessemer converter uses air/oxygen injection to oxidise excess carbon, silicon, and manganese from pig iron, converting it to steel.

Q29.

Pig iron (cast iron) differs from steel in that it:

  • A Contains more carbon (2-4% C) and is more brittle; steel has 0.1-1.5% C
  • B Actually contains less carbon than steel does
  • C Is a noticeably purer form of iron than steel
  • D Is always used directly in construction without any further conversion
Show answer & explanation

Answer: A. Contains more carbon (2-4% C) and is more brittle; steel has 0.1-1.5% C

Why: Pig iron from the blast furnace has 2-4% carbon and other impurities; it is brittle. Steel is pig iron with carbon reduced and controlled (0.1-1.5%) for strength and ductility.

Q30.

The Van Arkel-de Boer process purifies metals by:

  • A Forming a volatile iodide (e.g., TiI4) that is thermally decomposed to deposit pure metal and I<sub>2</sub> which is recycled
  • B Direct electrolysis of the molten metal halide using an inert graphite electrode cell as widely reported in standard practice
  • C Zone refining by slowly passing a localised molten zone repeatedly along the metal rod under most conditions encountered
  • D Froth flotation using pine oil as a frother together with a suitable sulfide collector as frequently observed in practice
Show answer & explanation

Answer: A. Forming a volatile iodide (e.g., TiI4) that is thermally decomposed to deposit pure metal and I<sub>2</sub> which is recycled

Why: The Van Arkel process: impure Ti + I<sub>2</sub> → TiI4 (volatile) at ~250°C; TiI4 is then decomposed at ~1400°C to give pure Ti and I<sub>2</sub>.

Q31.

Mond process is used to purify:

  • A Nickel: Ni + 4CO → Ni(CO)<sub>4</sub> (volatile) at 50-60°C; decomposed at 180-230°C to deposit pure Ni
  • B Iron, which is instead purified by oxidation in a Bessemer-type converter in many documented cases
  • C Copper, which is instead purified by electrolytic refining according to conventional understanding
  • D Zinc, which is instead purified by fractional distillation in routine practice overall
Show answer & explanation

Answer: A. Nickel: Ni + 4CO → Ni(CO)<sub>4</sub> (volatile) at 50-60°C; decomposed at 180-230°C to deposit pure Ni

Why: The Mond process forms nickel carbonyl (volatile) from impure Ni and CO; it is transported and decomposed at higher temperature to deposit pure Ni.

Q32.

The poling process in copper refining uses:

  • A Green wood poles stirred in molten blister copper to reduce Cu<sub>2</sub>O to Cu using hydrocarbons
  • B An electrolytic cell with a pure copper cathode and impure copper anode in most cases
  • C Solid coke added directly to the molten copper bath under typical conditions according to standard textbooks
  • D Zone refining by passing a molten zone along a copper bar in general practice as frequently described
Show answer & explanation

Answer: A. Green wood poles stirred in molten blister copper to reduce Cu<sub>2</sub>O to Cu using hydrocarbons

Why: Poling: green wood introduces hydrocarbons that reduce Cu<sub>2</sub>O (from over-oxidation): Cu<sub>2</sub>O + C → 2Cu + CO.

Q33.

Which metal is obtained as a byproduct during electrolytic refining of copper?

  • A Silver, gold, and platinum group metals collect as anode mud
  • B Iron, which dissolves alongside copper and deposits at the cathode
  • C Zinc, which collects together with the precious metals in the anode mud
  • D Aluminium, which is recovered from the copper sulfate electrolyte
Show answer & explanation

Answer: A. Silver, gold, and platinum group metals collect as anode mud

Why: Noble metals (Ag, Au, Pt) do not dissolve from the anode during Cu electrolytic refining; they fall off as anode sludge/mud and are recovered.

Q34.

Wrought iron is:

  • A The purest form of iron (<0.2% C), malleable and tough
  • B Essentially the same as pig iron, with a similarly high carbon content
  • C Identical to cast iron, sharing its characteristic brittleness
  • D A modern steel alloy containing significant chromium and nickel
Show answer & explanation

Answer: A. The purest form of iron (<0.2% C), malleable and tough

Why: Wrought iron is almost pure iron (0.1-0.2% C) made by removing impurities from pig iron; it is malleable, ductile, and resistant to corrosion.

Q35.

The Hall-Heroult cell electrolyses molten Al<sub>2</sub>O<sub>3</sub> at about:

  • A 950-1000°C in cryolite (melting point lowered from 2050°C of pure Al<sub>2</sub>O<sub>3</sub>)
  • B Ordinary room temperature, since cryolite fully dissolves Al<sub>2</sub>O<sub>3</sub> cold
  • C Around 100°C, the boiling point of water used to cool the cell
  • D Around 3000°C, close to the melting point of pure Al<sub>2</sub>O<sub>3</sub> alone
Show answer & explanation

Answer: A. 950-1000°C in cryolite (melting point lowered from 2050°C of pure Al<sub>2</sub>O<sub>3</sub>)

Why: Pure Al<sub>2</sub>O<sub>3</sub> melts at 2050°C; dissolving it in cryolite (Na3AlF6) reduces the operating temperature to ~950-1000°C, making the process practical.

Q36.

Which process is used to extract copper from low-grade sulfide ore?

  • A Hydrometallurgy (bioleaching or acid leaching + solvent extraction + electrowinning)
  • B A blast furnace process identical to that used for iron extraction in most textbook accounts
  • C The Hall-Heroult electrolytic process used instead for aluminium during normal conditions
  • D The thermite reaction used instead for welding iron rails as generally observed
Show answer & explanation

Answer: A. Hydrometallurgy (bioleaching or acid leaching + solvent extraction + electrowinning)

Why: Low-grade Cu ores are heap-leached with dilute H<sub>2</sub>SO<sub>4</sub> (bacterial oxidation helps); Cu<sup>2+</sup> in solution is extracted and electrowon as pure Cu.

Q37.

Which gas is used as reducing agent in extracting zinc by pyrometallurgy?

  • A Carbon monoxide (from coke): ZnO + CO → Zn + CO<sub>2</sub>
  • B Hydrogen gas injected directly into the roasting furnace
  • C Molten aluminium added as the reducing agent for zinc oxide
  • D Calcium metal added as the reducing agent for zinc oxide
Show answer & explanation

Answer: A. Carbon monoxide (from coke): ZnO + CO → Zn + CO<sub>2</sub>

Why: ZnO + C → Zn + CO (at ~1000°C); Zn vapour is condensed. The reaction produces Zn vapour because Zn's boiling point (907°C) is below the reaction temperature.

Q38.

Electrolytic reduction is necessary for active metals (like Al, Mg, Na) because:

  • A Their oxide formation Delta_G is too large; no chemical reducing agent (not even C) can reduce them at practical temperatures
  • B These particular metals are generally too rare in nature to ever justify any chemical reduction step in typical laboratory settings
  • C These particular metals are inexpensive enough that electrolysis is preferred for cost reasons regardless under usual circumstances
  • D These particular metals form unusually volatile oxide compounds that evaporate away before reduction begins according to most researchers
Show answer & explanation

Answer: A. Their oxide formation Delta_G is too large; no chemical reducing agent (not even C) can reduce them at practical temperatures

Why: Al, Mg, and Na oxides have very large negative Delta_G of formation; on the Ellingham diagram, no chemical reductant's line passes below these even at the highest temperatures.

Q39.

In the Down's cell (Na extraction), addition of CaCl<sub>2</sub> to NaCl:

  • A Lowers the melting point from 800°C to ~600°C and increases conductivity
  • B Produces calcium metal as the main electrolysis product instead
  • C Acts as an oxidising agent that consumes the sodium metal formed
  • D Directly reduces sodium ions to sodium metal without electrolysis
Show answer & explanation

Answer: A. Lowers the melting point from 800°C to ~600°C and increases conductivity

Why: CaCl<sub>2</sub> acts as a flux; the NaCl/CaCl<sub>2</sub> mixture melts at ~600°C vs 800°C for pure NaCl, saving energy and preventing Na vaporisation.

Q40.

The liquation process purifies metals with:

  • A Low melting points (like Sn, Bi, Pb) by gently heating on a slope so pure metal flows away from impurities
  • B Unusually high melting points that instead require an electric arc furnace to process them in the majority of cases studied
  • C Vacuum distillation of the molten metal carried out under significantly reduced pressure as widely reported
  • D Zone refining mainly, with little thermal gradient on a heated slope involved in standard practice under most conditions encountered
Show answer & explanation

Answer: A. Low melting points (like Sn, Bi, Pb) by gently heating on a slope so pure metal flows away from impurities

Why: Liquation heats impure low-melting-point metals on a sloped hearth; the pure metal melts and flows out, leaving higher-melting impurities behind.

Hard - 20 questions

Q41.

In the Ellingham diagram, why does the carbon (C→CO) line have a negative slope while most metal oxide lines have positive slopes?

  • A C→CO reaction: solid+gas→gas, Delta_S > 0; most MO formations: solid+gas→solid, Delta_S < 0. Delta_G = Delta_H - T*Delta_S, so the C line decreases and MO lines increase with T
  • B Carbon metal is generally assumed by convention to be far more chemically reactive than literally every other metal at every conceivable temperature in standard practice under most conditions encountered
  • C Most of the various metal oxide lines are generally assumed by convention to remain permanently positioned above the carbon line at most temperature as frequently observed in practice
  • D The observed slopes shown on the diagram for these lines are assumed by convention to have highly no underlying relationship to the entropy change of each reaction in many documented cases
Show answer & explanation

Answer: A. C→CO reaction: solid+gas→gas, Delta_S > 0; most MO formations: solid+gas→solid, Delta_S < 0. Delta_G = Delta_H - T*Delta_S, so the C line decreases and MO lines increase with T

Why: For 2C + O<sub>2</sub> → 2CO: moles of gas increase (Delta_S > 0), so Delta_G decreases with T (more negative). For M + O<sub>2</sub> → MO<sub>2</sub>: moles of gas decrease (Delta_S < 0), so Delta_G increases with T.

Q42.

The concentration of copper ore by froth flotation uses pine oil as a frother and xanthate as collector. The xanthate:

  • A Chemisorbs on sulfide surfaces via dithioate (CSS-) group coordination to Cu/Fe/Zn ions, making the surface strongly hydrophobic
  • B Generally dissolves largely into the surrounding water without ever binding to any mineral surface according to conventional understanding
  • C Acts as a chemical reducing agent that directly converts the metal sulfide into the free elemental metal in routine practice
  • D Functions mainly as a surfactant whose sole job is to stabilise the rising froth bubbles overall in most cases under typical conditions
Show answer & explanation

Answer: A. Chemisorbs on sulfide surfaces via dithioate (CSS-) group coordination to Cu/Fe/Zn ions, making the surface strongly hydrophobic

Why: Xanthate (RO-CS2-) binds strongly to metal sulfide surfaces via dative bonding of the sulfur atoms to surface metal ions, making the sulfide particles hydrophobic and float.

Q43.

In the Bayer process, what prevents the reverse reaction (reprecipitation) of Al(OH)<sub>3</sub> at the digestion stage?

  • A High temperature and NaOH concentration in the digester shift equilibrium toward NaAl(OH)4; cooling and seeding precipitate Al(OH)<sub>3</sub> controlled
  • B Generally adding a very large excess of plain water directly into the digester at most stage according to standard textbooks in general practice
  • C Keeping the digester deliberately held at an unusually low temperature throughout the entire digestion as frequently described in most textbook accounts
  • D Continuously bubbling carbon dioxide gas all the way through the hot digester liquor at every stage during normal conditions as generally observed
Show answer & explanation

Answer: A. High temperature and NaOH concentration in the digester shift equilibrium toward NaAl(OH)4; cooling and seeding precipitate Al(OH)<sub>3</sub> controlled

Why: The Bayer process uses Ostwald ripening control: cooling of the aluminate solution with seed crystals of Al(OH)<sub>3</sub> causes selective precipitation; temperature, NaOH concentration, and seeding are carefully controlled.

Q44.

Why can aluminium not be extracted by carbon reduction despite being cheaper than electrolysis?

  • A Al<sub>2</sub>O<sub>3</sub> has a very large and negative Delta_G of formation; the C/CO Ellingham line never crosses below Al<sub>2</sub>O<sub>3</sub> at any practical temperature
  • B Carbon is generally far too expensive a reducing agent to ever be used for large-scale aluminium extraction in typical laboratory settings
  • C Aluminium metal instead reacts with the carbon furnace lining itself to contaminate the final metal product under usual circumstances
  • D Electrolysis is preferred mainly as a matter of historical industrial convention rather than for any thermodynamic reason according to most researchers
Show answer & explanation

Answer: A. Al<sub>2</sub>O<sub>3</sub> has a very large and negative Delta_G of formation; the C/CO Ellingham line never crosses below Al<sub>2</sub>O<sub>3</sub> at any practical temperature

Why: Even at 3000°C, the C→CO line is above the Al→Al<sub>2</sub>O<sub>3</sub> line on the Ellingham diagram; thermodynamics forbids C from reducing Al<sub>2</sub>O<sub>3</sub>. At extremely high T, aluminium carbide forms instead.

Q45.

During the electrolysis of molten cryolite-alumina in the Hall-Heroult cell, the carbon anode is consumed because:

  • A CO<sub>2</sub> and CO form as anode gases from oxidation of C by O<sup>2-</sup> ions: C + 2O<sup>2-</sup> → CO<sub>2</sub> + 4e-
  • B The carbon anode gradually dissolves directly into the molten aluminium product
  • C The carbon anode itself chemically reduces the surrounding Al<sub>2</sub>O<sub>3</sub> to aluminium
  • D The carbon anode functions as a flux that lowers the electrolyte's melting point
Show answer & explanation

Answer: A. CO<sub>2</sub> and CO form as anode gases from oxidation of C by O<sup>2-</sup> ions: C + 2O<sup>2-</sup> → CO<sub>2</sub> + 4e-

Why: At the carbon anode, O<sup>2-</sup> from Al<sub>2</sub>O<sub>3</sub> oxidises the carbon: 2O<sup>2-</sup> → O<sub>2</sub> + 4e-; but the O<sub>2</sub> immediately reacts with the hot carbon anode to give CO/CO<sub>2</sub>. Anodes are regularly replaced.

Q46.

The thermite reaction is used for welding railway lines because:

  • A It is a highly exothermic self-sustaining reaction producing molten iron in situ; no external heat source needed after ignition
  • B Iron metal supposedly happens to already be readily available in bulk at most rail site in the majority of cases studied as widely reported
  • C It produces a slag byproduct that supposedly conveniently fills in any leftover gaps in the rail joint in standard practice
  • D It supposedly relies largely on a portable electrical generator to drive the reaction at each rail site under most conditions encountered
Show answer & explanation

Answer: A. It is a highly exothermic self-sustaining reaction producing molten iron in situ; no external heat source needed after ignition

Why: Delta_H for 2Al + Fe2O<sub>3</sub> → Al<sub>2</sub>O<sub>3</sub> + 2Fe is about -852 kJ/mol; the molten iron produced (~2500°C) fills the weld gap and solidifies in place.

Q47.

In electrorefining, the anode potential is set carefully to:

  • A Dissolve only the metal being refined (e.g., Cu), not impurities above it (Ag, Au) or those below that fall off without dissolving
  • B Dissolve highly every metal present in the impure anode simultaneously and largely indiscriminately as frequently observed in practice
  • C Deliberately deposit most of the impurity metals directly onto the cathode right alongside the pure metal in many documented cases
  • D Prevent any and all dissolution of the impure anode from occurring throughout the entire electrolysis according to conventional understanding
Show answer & explanation

Answer: A. Dissolve only the metal being refined (e.g., Cu), not impurities above it (Ag, Au) or those below that fall off without dissolving

Why: Anode potential is set between Cu (dissolves, E° -0.34V vs SHE as cathode/+0.34 as anode) and noble metals (Ag, Au, Pt) which remain as anode mud; less noble impurities (Ni, Fe) dissolve but don't plate at cathode (Cu is preferentially plated).

Q48.

Zone refining works on the principle that:

  • A Impurities have different solubility (distribution coefficient k) in solid vs liquid phases; most impurities are more soluble in the melt
  • B Impurities generally evaporate largely away from the metal rod as the heated molten zone slowly passes in routine practice overall in most cases
  • C The molten heating zone is deliberately kept at a temperature below the metal's actual melting point under typical conditions according to standard textbooks
  • D The specific impurities being removed by this process are inherently magnetic substances by nature in general practice as frequently described
Show answer & explanation

Answer: A. Impurities have different solubility (distribution coefficient k) in solid vs liquid phases; most impurities are more soluble in the melt

Why: Distribution coefficient k = Cs/Cl (concentration in solid/liquid). For k < 1, impurities prefer the liquid zone and are swept toward one end of the ingot.

Q49.

The Mond process uses 4CO per Ni atom. Why does CO work and not other gases?

  • A CO is a unique sigma donor and pi-acceptor that forms a very stable, volatile carbonyl with Ni(0) at low temperature; other gases don't have this property
  • B Carbon monoxide is generally the cheapest industrial gas available anywhere for large-scale metallurgical processing in most textbook accounts during normal conditions
  • C Nickel metal is supposedly uniquely capable among all metals of physically absorbing almost any gas indiscriminately as generally observed in typical laboratory settings
  • D Carbon monoxide supposedly reacts selectively mainly with the impurity metals present, leaving the nickel largely untouched under usual circumstances
Show answer & explanation

Answer: A. CO is a unique sigma donor and pi-acceptor that forms a very stable, volatile carbonyl with Ni(0) at low temperature; other gases don't have this property

Why: Ni(CO)<sub>4</sub> forms because Ni(0) has filled d orbitals for pi-backbonding into CO pi* orbitals; the carbonyl is volatile (bp 43°C) allowing easy separation and thermal decomposition.

Q50.

Bioleaching uses bacteria to extract copper from low-grade ores. The bacteria involved (e.g., Acidithiobacillus ferrooxidans) catalyse:

  • A Oxidation of Fe<sup>2+</sup> to Fe<sup>3+</sup> (which then oxidises sulfide mineral) and oxidation of CuS/Cu2S to CuSO<sub>4</sub>
  • B The direct reduction of the dissolved Cu<sup>2+</sup> ions all the way down to metallic elemental copper
  • C The straightforward dissolution of the silica gangue minerals scattered within the ore body
  • D The complete neutralisation of the acidic bioleaching solution back to a roughly neutral pH
Show answer & explanation

Answer: A. Oxidation of Fe<sup>2+</sup> to Fe<sup>3+</sup> (which then oxidises sulfide mineral) and oxidation of CuS/Cu2S to CuSO<sub>4</sub>

Why: Bacteria regenerate Fe<sup>3+</sup> which is the actual oxidant: Cu2S + 2Fe<sup>3+</sup> → 2Cu<sup>2+</sup> + 2Fe<sup>2+</sup> + S; bacteria then reoxidise Fe<sup>2+</sup> → Fe<sup>3+</sup> completing the cycle.

Q51.

The basic oxygen furnace (BOF) replaced the Bessemer converter because:

  • A Pure O<sub>2</sub> injection (instead of air) avoids nitrogen absorption into steel, gives faster processing, and better temperature control
  • B The basic oxygen furnace is said to generally consume far less total energy per tonne of finished steel according to most researchers
  • C The basic oxygen furnace was supposedly significantly cheaper to construct than any Bessemer converter in the majority of cases studied
  • D Ordinary atmospheric air supposedly reacts with the dissolved carbon far more efficiently than pure oxygen as widely reported
Show answer & explanation

Answer: A. Pure O<sub>2</sub> injection (instead of air) avoids nitrogen absorption into steel, gives faster processing, and better temperature control

Why: Air injection in Bessemer introduced N<sub>2</sub> (causing embrittlement); BOF uses pure O<sub>2</sub>, producing better quality steel faster (20-40 min vs Bessemer's 15 min but with N issues).

Q52.

The Van Arkel de Boer process can only be applied to metals that:

  • A Form volatile iodides at moderate temperature that decompose at higher temperature (e.g., Ti, Zr, Hf, Nb, Ta, V, B, Si)
  • B Highly most metal found anywhere on the entire periodic table without any exception in standard practice under most conditions encountered
  • C Any transition metal whatsoever, largely regardless of whether its halide is volatile or not as frequently observed in practice
  • D Metals that generally happen to possess an unusually low melting point compared to other metals in many documented cases
Show answer & explanation

Answer: A. Form volatile iodides at moderate temperature that decompose at higher temperature (e.g., Ti, Zr, Hf, Nb, Ta, V, B, Si)

Why: The Van Arkel process requires: (1) impure metal reacts with I<sub>2</sub> to form volatile MI4/MI3; (2) the iodide must decompose at higher temperature to deposit pure metal. Ti, Zr, and similar reactive metals meet this criteria.

Q53.

Hydrometallurgy involves which steps in sequence?

  • A Leaching (dissolve metal) → Purification/Separation (SX/IX) → Reduction (electrolysis or cementation)
  • B Roasting → Smelting → Refining, the classic pyrometallurgical sequence instead according to conventional understanding
  • C Ore crushing → Froth flotation → Smelting, a concentration-then-pyrometallurgy sequence in routine practice
  • D Direct reduction → Casting, skipping any aqueous dissolution step largely overall in most cases
Show answer & explanation

Answer: A. Leaching (dissolve metal) → Purification/Separation (SX/IX) → Reduction (electrolysis or cementation)

Why: Hydrometallurgy sequence: selective dissolution of metal into solution (leaching) → separation from impurities (solvent extraction, ion exchange) → recovery of pure metal (electrowinning or chemical reduction).

Q54.

In steel production, what is the role of ferro-manganese addition?

  • A Deoxidises and desulfurises the melt: Mn + S → MnS (slag); Mn + FeO → MnO + Fe
  • B Deliberately increases the carbon content of the finished steel under typical conditions
  • C Acts mainly as a flux to lower the slag's melting point according to standard textbooks
  • D Lowers the overall temperature required during steel production in general practice
Show answer & explanation

Answer: A. Deoxidises and desulfurises the melt: Mn + S → MnS (slag); Mn + FeO → MnO + Fe

Why: Manganese (as FeMn) is added to steel to remove dissolved oxygen (deoxidation) and sulfur (desulfurisation), preventing hot shortness and porosity.

Q55.

What is the distribution ratio (D) in solvent extraction and why is it important?

  • A D = [metal in organic phase]/[metal in aqueous phase]; high D means efficient extraction in fewer stages
  • B D generally represents the relative density ratio measured between the two immiscible liquid phases
  • C D supposedly indicates mainly the absolute solubility of the metal salt dissolved in plain water as frequently described
  • D D is supposedly just a numerical measure of the temperature difference between the two phases in most textbook accounts
Show answer & explanation

Answer: A. D = [metal in organic phase]/[metal in aqueous phase]; high D means efficient extraction in fewer stages

Why: A high D means most of the metal partitions into the organic solvent, allowing efficient separation from other metals that have different D values; it determines the number of extraction stages needed.

Q56.

High purity silicon (99.9999%) for semiconductors is obtained from metallurgical grade Si by:

  • A Zone refining after converting to SiHCl3 (trichlorosilane) and purifying by fractional distillation, then reducing: SiHCl3 + H<sub>2</sub> → Si
  • B Direct zone refining of the raw metallurgical-grade silicon ore without any chemical conversion step during normal conditions as generally observed
  • C A single-step direct electrolysis of molten silicon dioxide in a graphite-lined electrolytic cell in typical laboratory settings
  • D The Bayer process, which is instead normally used to purify bauxite ore into pure alumina under usual circumstances according to most researchers
Show answer & explanation

Answer: A. Zone refining after converting to SiHCl3 (trichlorosilane) and purifying by fractional distillation, then reducing: SiHCl3 + H<sub>2</sub> → Si

Why: The Siemens process: Si + HCl → SiHCl3 (volatile); SiHCl3 is distilled to remove impurities; H<sub>2</sub> reduction deposits ultrapure Si. Then zone refining achieves parts-per-billion purity.

Q57.

The free energy change for the reaction Fe2O<sub>3</sub> + 3CO → 2Fe + 3CO<sub>2</sub> becomes negative (spontaneous) only above a certain temperature. This critical temperature is approximately:

  • A 700°C (Ellingham diagram crossover between C/CO line and Fe2O<sub>3</sub> line)
  • B 0°C, the freezing point of water rather than any meaningful crossover temperature
  • C 1500°C, far above the actual Ellingham crossover for this pair of lines
  • D 25°C, ordinary room temperature with no special thermodynamic significance here
Show answer & explanation

Answer: A. 700°C (Ellingham diagram crossover between C/CO line and Fe2O<sub>3</sub> line)

Why: The C→CO line on the Ellingham diagram crosses below the Fe→Fe2O<sub>3</sub> line at about 700°C; above this T, CO reduction of Fe2O<sub>3</sub> is spontaneous; the actual blast furnace operates at ~1500-1700°C for complete reduction.

Q58.

In froth flotation, depressants are used to:

  • A Selectively prevent certain minerals from floating (e.g., NaCN depresses ZnS allowing PbS to float separately)
  • B Promote every mineral present in the ore to float together indiscriminately in the majority of cases studied
  • C Generally lower the pH of the flotation cell without affecting any mineral surface as widely reported in standard practice
  • D Raise the temperature of the flotation cell to speed up bubble formation under most conditions encountered
Show answer & explanation

Answer: A. Selectively prevent certain minerals from floating (e.g., NaCN depresses ZnS allowing PbS to float separately)

Why: Depressants (NaCN, ZnSO<sub>4</sub>) make certain mineral surfaces hydrophilic, preventing them from floating, allowing selective separation of one sulfide mineral from another.

Q59.

In the upper zones of a blast furnace, the iron oxide ore is reduced mainly by:

  • A coke burning directly
  • B carbon monoxide gas
  • C calcium oxide flux
  • D molten silica slag
Show answer & explanation

Answer: B. carbon monoxide gas

Why: In the cooler upper region, CO reduces the ore: Fe₂O₃ + 3CO → 2Fe + 3CO₂. Direct reduction by coke dominates only in the hotter lower zone.

Q60.

In froth flotation, collectors such as pine oil work by making the mineral particles:

  • A dissolve into the gangue
  • B water-repellent (hydrophobic)
  • C water-wettable (hydrophilic)
  • D fuse into a slag
Show answer & explanation

Answer: B. water-repellent (hydrophobic)

Why: Collectors coat the ore particles making them hydrophobic, so they attach to air bubbles and rise with the froth while the gangue sinks.