Zaymiey

🧪 Chemistry  ·  Redox Reactions  ·  NEET & JEE

The reaction: 5H2O2 + 2KMnO4 + 3H2SO4 → 2MnSO4 + K2SO4 + 5O2 + 8H2O shows that H2O2 is acting as:

Answer: Reducing agent (H2O2 is oxidised: O from -1 to 0 in O2).

  • A Oxidising agent (Mn7+ → Mn2+, so KMnO4 is reduced by H2O2)
  • B Reducing agent (H2O2 is oxidised: O from -1 to 0 in O2)
  • C Catalyst
  • D Neither oxidised nor reduced

Correct answer: B. Reducing agent (H2O2 is oxidised: O from -1 to 0 in O2)

Explanation: In this reaction, H₂O₂ is the reducing agent: O in H₂O₂ goes from -1 to 0 in O₂ (loses electrons, oxidised). KMnO₄ is the oxidising agent: Mn goes from +7 to +2 (gains electrons, reduced).

Electron Transfer: Zn + Cu²⁺ → Zn²⁺ + CuZnloses 2e⁻OXIDISED (Zn → Zn²⁺)2e⁻Cu²⁺gains 2e⁻REDUCED (Cu²⁺ → Cu)Zn = reducing agentCu²⁺ = oxidising agent

Electron transfer in a redox reaction: zinc loses electrons (oxidised, acts as reducing agent) and copper(II) ions gain those same electrons (reduced, acts as oxidising agent).

Concept context

Master electron transfer in chemistry: assign oxidation states, balance half-reactions, identify oxidising and reducing agents, and connect redox to everyday reactions.

Read the full Redox Reactions notes →